Question

A cable of resistance $10\Omega$ carries electric power from a generator producing 250 kW at 10000 volt. The current in the cable is

• A. 25 A
• B. 250 A
• C. 100 A
• D. 1000 A

Answer 1

Answer: (A)

25 A

Answer 2

Since $P = VI$ ⇒ $I = \frac{P}{V} = \frac{250000}{10000} = 25A$