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Question: A bus moves with an average speed of 60 kilometers per hour for 4.5 hours. Find the distance travele...

A bus moves with an average speed of 60 kilometers per hour for 4.5 hours. Find the distance traveled by it.

Explanation

Solution

Average speed is the ratio of total distance to the total time taken. It is given by the equation
vavg=xt{v_{avg}} = \dfrac{x}{t}
Where, xx is the total distance and tt is the time taken
Using this equation we can find the total distance travelled.

Complete step by step answer:
Given,
The average speed of the bus, vavg{v_{avg}} is 60km/hr60\,km/hr.
1km1\,km is 1000m1000\,m.
1hr1\,hr is 60min60\,\min .
1min1\min is 60s60\,s.
1hr=60×60s=3600s\therefore 1\,hr = 60 \times 60\,s = 3600\,s
So, in order to convert 60km/hr60\, km/hr into m/sm/s we need to multiply the numerator by 1000 and denominator by 3600.
That is,
vavg=60km1hr=60×10001×3600=16.66m/s{v_{avg}} = \dfrac{{60\,km}}{{1\,hr}} = \dfrac{{60\, \times 1000}}{{1 \times 3600}} = 16.66\,m/s
Time taken is given as 45hr45\,hr. Thus,
t=45hr=45×3600s=16200st = 45\,hr = 45 \times 3600\,s = 16200\,s
We need to find the distance travelled by the bus.
Average speed is the ratio of total distance to the total time taken. It is given by the equation
vavg=xt{v_{avg}} = \dfrac{x}{t}
Where xx is the total distance and tt is the time taken
From this we can calculate the distance as
x=vavg×tx = {v_{avg}} \times t
Substitute the given values then we get
x=16.666×16200\Rightarrow x = 16.666 \times 16200
x=269892m\Rightarrow x = 269892\,m
x=269.8km\Rightarrow x = 269.8\,km
x270kmx \approx 270\,km

Therefore, the distance traveled by bus is 270km.

Note:
Speed is a scalar quantity. It has only magnitude. This is because the distance is a scalar quantity. Distance is the length of the path traveled. Hence it does not have a direction.
Whereas the average velocity calculated using displacement is a vector quantity. Displacement is the shortest path traveled. It has both magnitude and direction.