Question
Question: A bullet shot from a rifle at \(25m\) range strikes the target at a point \(4.9cm\) below the point ...
A bullet shot from a rifle at 25m range strikes the target at a point 4.9cm below the point at which the barrel is pointing horizontally. The muzzle velocity of the bullet is
A. 50ms−1
B. 100ms−1
C. 125ms−1
D. 250ms−1
Solution
Before proceeding with the solution, first convert all the given terms in the same system of units. Then use the second equation of motion in the vertical direction - S=ut+21gt2 and the velocity that is distance travelled per time taken. Substitute known values and find the unknown terms.
Complete step by step answer:
Distance travelled by the bullet is d=25m
Bullet strikes the target at a point, s=4.9cm=0.049m
Gravitational acceleration, g=9.8m/s2
Initial velocity, u=0m/s
Now, according to the second equation of the motion in the vertical direction –
S=ut+21gt2
Place the known values in the above equation and make unknown “t” the subject –
0.049=0+21×9.8×t2
Simplify the above equation –
Now, velocity is distance per time taken.
Therefore, the muzzle velocity of the bullet is
v=td
Place the known values in the above equation –
\implies v = \dfrac{{25}}{{0.1}} \\\
∴v=250m/s
Therefore, the required answer - The muzzle velocity of the bullet is 250m/s
So, the correct answer is “Option D”.
Note:
Remember basic formulas for velocity and its laws of equations to solve these types of sums. Also, always double check the given units in all the terms and the units of the answer required. All the terms should have the same format of units. There are three systems of units.
- MKS unit (Meter Kilogram Second)
- CGS unit (Centimetre gram Second)
- SI unit (System International)