Solveeit Logo

Question

Physics Question on collision theory

A bullet of mass 50 g is fired from a 5 kg gun with a velocity of 1 km/sec. The speed of recoil of the gun is:

A

5 m/s

B

1 m/s

C

0.5 m/s

D

10 m/s

Answer

10 m/s

Explanation

Solution

Applying law of conservation or momentum mv = mυmv\text{ }=\text{ }m\upsilon Here, mass of bullet m=50 g=0.05 kgm=50\text{ }g=0.05\text{ }kg velocity of bullet =1 km/sec=1000 m/sec=1\text{ }km\text{/}sec=1000\text{ }m\text{/}sec mass of gun m=5kgm=5kg or 0.05×1000=5v0.05\times 1000=5v or v=0.05×10005v=\frac{0.05\times 1000}{5} so, v=10m/sv=10\,m\text{/}s