Question
Question: A bullet of mass 10g traveling horizontally with a velocity of 150\(m{s}^{-1}\) strikes a stationary...
A bullet of mass 10g traveling horizontally with a velocity of 150ms−1 strikes a stationary wooden block and comes to rest in 0.03s. Calculate the distance of penetration of the bullet into the block. Also, calculate the magnitude of the force exerted by the wooden block on the bullet.
Solution
Newton’s law gives a relation between a body which is motion and forces acting on that body. The three laws of Newton are used for the following questions. The four basic Newton’s equation of motion is used. According to the question and data provided we have to form an equation and substitute the given values in the equation.
Formula used:
Equation of motion
v=u+at
v2=u2+2as
F=ma
Complete step-by-step solution:
Let u be the initial velocity of bullet travelling with acceleration a in time t seconds. v be the final velocity of bullet
Given-
Initial velocity u=150m/s
Final velocity v=0
Mass m=10g=0.01kg
Time t=0.03s
Applying Newton's equation