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Question

Physics Question on work, energy and power

A bullet of mass 10 g leaves a rifle at an initial velocity of 1000 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joule overcoming the resistance of air will be

A

375

B

3750

C

5000

D

500

Answer

3750

Explanation

Solution

Work done = change in kinetic energy of the body
W=12×0.01[(1000)2(500)2]=3750joule.\, \, W=\frac{1}{2} \times \, 0.01[(1000)^2-(500)^2]=3750 \,joule.