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Question: A bullet of mass 0.1 kg is fired with a speed of 100 m/sec, the mass of gun is 50 kg. The velocity o...

A bullet of mass 0.1 kg is fired with a speed of 100 m/sec, the mass of gun is 50 kg. The velocity of recoil is

A

0.2 m/sec

B

0.1 m/sec

C

0.5 m/sec

D

0.05 m/sec

Answer

0.2 m/sec

Explanation

Solution

According to principle of conservation of linear momentum, mGvG=mBvBm_{G}v_{G} = m_{B}v_{B}

\Rightarrow vG=mBvBmG=0.1×10250=0.2m/sv_{G} = \frac{m_{B}v_{B}}{m_{G}} = \frac{0.1 \times 10^{2}}{50} = 0.2m ⥂ / ⥂ s