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Question

Physics Question on Motion in a plane

A bullet of mass 0.1kg0.1 \,kg is fired with a speed of 100m/s.100 \,m/s. The mass of gun being 50kg50 \,kg. Then, the velocity of recoil become:

A

0.05 m/s

B

0.5 m/s

C

0.1 m/s

D

0.2 m/s

Answer

0.2 m/s

Explanation

Solution

In absence of any external force, linear momentum of a system is conserved..
Linear momentum of bullet-gun system is conserved.
i.e.. Initial momentum = Final momentum
0=m1v1+m2v2\therefore 0=m_{1} \,v_{1}+m_{2}\, v_{2}
or 0=0.1×100+50×v20=0.1 \times 100+50 \times v_{2}
v2=1050=0.2m/s\therefore v_{2}=-\frac{10}{50}=-0.2 \,m / s
Negative sign implies recoil.
Hence, the velocity of recoil is 0.2m/s0.2\, m / s.