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Question: A bullet is fired morally towards an immovable wooden block. It loses \[25\% \]of its kinetic energy...

A bullet is fired morally towards an immovable wooden block. It loses 25%25\% of its kinetic energy in penetrating through a thickness xx of the plank the bullet into the block is:
(A) 4x4x
(B) 6x6x
(C) 8x8x
(D) 2x2x

Explanation

Solution

We know that kinetic energy is defined as the work needed to accelerate a body to a given mass from nest to its stated velocity on gaming this energy the body maintains until its speed changes.
Loss in kinetic energy =work done = work{\text{ }}done

Complete step by step answer:
We can consider the initial kinetic energy of the bullet is k and the resistance force experienced by the resistance the bullet is f now by using the work energy theorem for the first case.
Loss in kinetic energy =work done = work{\text{ }}done
k4=fx 4kx.......(1)  \Rightarrow \dfrac{k}{4} = fx \\\ \Rightarrow 4kx.......(1) \\\
We know the bullet will stop when kinetic energy is
Hence the change in kinetic energy will bekk.

Considering the bullet to be yy
Then using work energy theorem
k=fy.....(2)k = fy.....(2)
Form equation (1)and (2)\left( 1 \right)and{\text{ }}\left( 2 \right)
k=4fx=fy y=4x  k = 4fx = fy \\\ y = 4x \\\

So, the correct answer is “Option A”.

Note:
In physics the kinetic energy of an object is the energy that it derives due to its motion. Derivation form other quantities is
EK=12MV2,E=ET+ER{E_K} = \dfrac{1}{2}M{V^2},E = {E_T} + {E_R}