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Question

Physics Question on work, energy and power

A bullet is fired from a rifle and the rifle recoils. Kinetic energy of rifle is

A

less than K.E. of bullet

B

greater than K.E. of bullet

C

equal to K.E. of bullet

D

none of the above

Answer

greater than K.E. of bullet

Explanation

Solution

Momentum of rifle = Momentum of bullet m1v1=m2v2m_{1} v_{1}=m_{2} v_{2}, Also m1>m2m_{1} >m_{2}  K.E. of rifte  K.E. of bullet =12m1v1212m2v22\frac{\text { K.E. of rifte }}{\text { K.E. of bullet }}=\frac{\frac{1}{2} m_{1} v_{1}^{2}}{\frac{1}{2} m_{2} v_{2}^{2}} =m12v12m1m2m22v22=m2m1=\frac{m_{1}^{2} v_{1}^{2}}{m_{1}} \frac{m_{2}}{m_{2}^{2} v_{2}^{2}}=\frac{m_{2}}{m_{1}} K.E. of rifle is less than K.EK . E. of bullet.