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Question

Physics Question on Motion in a plane

A bullet is fired from a gun at the speed of 280 ms-1 in the direction 30° above the horizontal. The maximum height attained by the bullet is
(g = 9.8 ms-2, sin 30° = 0.5)

A

3000 m

B

2800 m

C

2000 m

D

1000 m

Answer

1000 m

Explanation

Solution

Given:
u=280 ms1u = 280\ ms^{-1}
θ=30\theta = 30\degree
g9.8 ms2g-9.8 \ ms^{-2}

The maximum height attained by the bullet,
Hmax=u2sin2θ2gH_{max}=\frac{u^2sin^2\theta}{2g}

Hmax=(280)2×(sin30)22(9.8)H_{max}=\frac{(280)^2\times(sin30^{\circ})^2}{2(9.8)}

Hmax=1000mH_{max}=1000\,m

So, the correct option is (D): 1000 m1000\ m