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Question: A bullet is fired from a canon with velocity 500 m/s. If the angle of projection is 15<sup>o</sup> a...

A bullet is fired from a canon with velocity 500 m/s. If the angle of projection is 15o and g = 10 m/s2. Then the range is

A

25 × 103m

B

12.5 × 103m

C

50× 102m

D

25 × 102m

Answer

12.5 × 103m

Explanation

Solution

Range(R)=u2sin2θg=(500)2sin(2×15)10Range(R) = \frac{u^{2}\sin 2\theta}{g} = \frac{(500)^{2}\sin(2 \times 15)}{10}

=12500m=12.5×103m= 12500m = 12.5 \times 10^{3}m