Solveeit Logo

Question

Physics Question on laws of motion

A bullet emerge from a barrel of length 1.2m1.2\, m with a speed of 640ms1640\, ms ^{-1}. Assuming constant acceleration, the approximate time that it spends in the barrel after the gun is fired is

A

4ms4\, ms

B

40ms40\, ms

C

400400 μs\mu\,s

D

1s1\,s

Answer

4ms4\, ms

Explanation

Solution

Given that, s=1.2ms=1.2\, m
and v=640ms1a=?;u=0;t=?v=640\, ms ^{-1} a=? ; u=0 ; t=?
We have the third equation of motion
2as=v2u22 a s =v^{2}-u^{2}
2a×1.2=640×6402 a \times 1.2 =640 \times 640
or a=8×64×1033a =\frac{8 \times 64 \times 10^{3}}{3}
and by first equation of motion
v=u+atv =u +a t
or t=va=154×103t =\frac{v}{a}=\frac{15}{4} \times 10^{-3}
=3.75×103=3.75 \times 10^{-3}
s=4mss=4\, ms