Question

A bulb has specification of one kilowatt and 250 volts, the resistance of bulb is

• A. 125 Ω
• B. 62.5 Ω
• C. 0.25 Ω
• D. 625 Ω

Answer 1

Answer: (B)

62.5 Ω

Answer 2

$R = \frac{V^{2}}{P} = \frac{(250)^{2}}{10^{3}} = 62.5\Omega$