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Question

Chemistry Question on Equilibrium

A buffer solution is prepared by mixing 10 mL of 1.0 M acetic acid and 20 mL of 0.5 M sodium acetate acid and then diluted to 100 mL with distilled water. If the pKapK_a of CH3COOHCH_3COOH is 4.76, what is the pH of the buffer solution prepared ?

A

5.21

B

4.76

C

4.34

D

5.22

Answer

4.76

Explanation

Solution

The expression for the pHpH of the acidic buffer solution is as given below. pH=pKa+log[ Salt ][ Acid ]pH = pK _{ a }+\log \frac{[\text { Salt }]}{[\text { Acid }]} pKa=4.76pK _{ a }=4.76 [Salt] =20×0.5100=0.1M=\frac{20 \times 0.5}{100}=0.1 M [Acid] =10×1100=0.1M=\frac{10 \times 1}{100}=0.1 M Substitute values in the above equation. pH=4.76+log0.10.1=4.76pH =4.76+\log \frac{0.1}{0.1}=4.76