Solveeit Logo

Question

Question: A buffer solution contains 0.1 mole of sodium acetate in 1000 cm3 of 0.1 M acetic acid, to the above...

A buffer solution contains 0.1 mole of sodium acetate in 1000 cm3 of 0.1 M acetic acid, to the above buffer solution, 0.1 M of sodium acetate is further added and dissolved. The pHpH of the resulting buffer is equal to:
A. pKalog2p{K_a} - \log 2
B. pKap{K_a}
C. pKa+2p{K_a} + 2
D. pKa+log2p{K_a} + \log 2

Explanation

Solution

Any solution whose pHpH is not altered to any extent by the addition of small quantities of acid or a base is called buffer solution. Or we can say a solution acidity or alkalinity which can resist change in pHpH upon addition of a small amount of acid or base. For the given question we will use Henderson’s equation:
pH=pKa+log[salt][acid]pH = pKa + \log \dfrac{{[salt]}}{{[acid]}}

Complete step by step answer:
According to the question the initial concentrations are:
[CH3COONa]=0.1  M\left[ {C{H_3}COONa} \right] = 0.1\;M and,
[CH2COOH]=0.1  M\left[ {C{H_2}COOH} \right] = 0.1\;M
After the addition of 0.1 mol CH3COONaC{H_3}COONa we get:
[CH3COONa]=0.1+0.1=0.2  M\left[ {C{H_3}COONa} \right] = 0.1 + 0.1 = 0.2\;M and,
[CH2COOH]=0.1  M\left[ {C{H_2}COOH} \right] = 0.1\;M
Now as we all know from Henderson’s equation (pHpH of a buffer) of acidic buffer:
pH=pKa+log[salt][acid]pH = pKa + \log \dfrac{{[salt]}}{{[acid]}}
pH=pKa+log[0.2][0.1] pH=pKa+log2  \Rightarrow pH = pKa + \log \dfrac{{[0.2]}}{{[0.1]}} \\\ \Rightarrow pH = pKa + \log 2 \\\

So, the correct answer is Option D .

Additional Information:
The property of a buffer solution to resist changes in pHpH value is known as buffer capacity. Experimentally it has been found that if ratio of [salt][acid]\dfrac{{[salt]}}{{[acid]}} or [salt][base]\dfrac{{[salt]}}{{[base]}} is 1, then pHpH of the buffer doesn’t change at all. So we can also say that, the number of moles of acid or base added to 1 litre of solution to change its pHpH by unity is called buffer capacity.
Buffers are used in industrial processes such as manufacture of paper, ink, drugs etc.

Note:
Buffer solution can be obtained by
Mixing weak acid with its salt with strong base
Mixing weak base with its salt with strong acid
From a solution of ampholyte. (These are the substances which show properties of both an acid and a base. Proteins and amino acids are examples for ampholyte.)
From a mixture of an acid salt and a normal salt of a polybasic acid.