Question

A bucket of water $50Kg$is raised from a depth$100m$. To the ground by a rope. The mass of the rope is $1Kg$ per meter of work done.

Answer 1

The most commonly used terms in Physics are work, energy, and power. They're most likely the first thing you learned in physics class. Work and energy can be thought of as two sides of a single coin.

Complete step by step solution:
Work is usually measured in terms of the force applied, whereas energy is measured in terms of other factors such as heat. Power is defined as the amount of work completed in a given amount of time.
Work: When a force is applied to an object, work is said to be completed. Work is calculated by multiplying the force by the object's movement.
$W\text{ }=\text{ }F\times d$
The joule is the SI unit of work ($J$).
Energy: In physics, energy is defined as the ability to perform work.
$P.E.\text{ }=\text{ }mgh$
Unit is the formula for potential energy.
The joule ($J$) is the SI unit of energy, and it was named after James Prescott Joule.
Power: Power is the rate at which work is completed, or energy is converted.
$P\text{ }=\text{ }\dfrac{W}{t}$
The watt is a power measurement unit ($W$).
Given,
Bucket of water =$50\text{ }kg$,
dept or height (h) = $10m$,
mass = $1\text{ }kg/m$
$g=9.8m/s$
Weight of bucket = $50\text{ }\times \text{ }9.8\text{ }\times \text{ }10$(work done in lifting)
= $4900J$
Mass of rope = $10\text{ }\times \text{ }1\text{ }kg$= $10\text{ }kg$
weight t of rope = $10\text{ }\times \text{ }9.8\text{ }=\text{ }98\text{ }N$
Work done in raising the bucket = $98\text{ }\times 10\text{ }=\text{ }980\text{ }J$
Total work done = $4900\text{ }+\text{ }980\text{ }=\text{ }5880\text{ }J$
Thus, the work done is$5880\text{ }J$.

Note:
In practice, whenever work is done to move energy from one form to another, other forms of energy, such as heat and sound, are always lost. For example, a traditional light bulb converts electrical energy to visible light at about 3% efficiency, whereas a human being converts chemical energy from food into work at about 25% efficiency.