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Question

Physics Question on Refraction of Light

A bubble in glass slab (μ=1.5)(\mu = 1.5) when viewed from one side appears at 5 cm and 2 cm from other side, then thickness of slab is

A

3.75 cm

B

3 cm

C

10.5 cm

D

2.5 cm

Answer

10.5 cm

Explanation

Solution

Total apparent depth,
y=y1+y2=5+2=7cmy=y_1 +y_2 = 5+2 =7 cm
If.v is real depth = thickness of slab, then as
μ=realdepthapparentdepth=xy\mu = \frac{real depth}{apparent depth} = \frac{x}{y}
orx=μy=1.5×7=10.5cm\, \, or \, \, x= \mu y = 1.5 \times 7 = 10.5 cm