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Question

Physics Question on mechanical properties of fluid

A bubble has surface tension SS. The ideal gas inside the bubble has ratio of specific heats γ=53\gamma=\frac{5}{3}. The bubble is exposed to the atmosphere and it always retains its spherical shape. When the atmospheric pressure is Pa1P_{a 1}, the radius of the bubble is found to be r1r_1 and the temperature of the enclosed gas is T1T_1. When the atmospheric pressure is Pa2P_{a 2}, the radius of the bubble and the temperature of the enclosed gas are r2r_2 and T2T_2, respectively.Which of the following statement(s) is(are) correct?

A

If the surface of the bubble is a perfect heat insulator, then (r1r2)5=Pa2+2Sr2Pa1+2Sr1\left(\frac{r_1}{r_2}\right)^5=\frac{P_{a 2}+\frac{2 S}{r_2}}{P_{a 1}+\frac{2 S}{r_1}}

B

If the surface of the bubble is a perfect heat insulator, then the total internal energy of the bubble including its surface energy does not change with the external atmospheric pressure.

C

If the surface of the bubble is a perfect heat conductor and the change in atmospheric temperature is negligible, then (r1r2)3=Pa2+4Sr2Pa1+4Sr1\left(\frac{r_1}{r_2}\right)^3=\frac{P_{a 2}+\frac{4 S}{r_2}}{P_{a 1}+\frac{4 S}{r_1}}.

D

If the surface of the bubble is a perfect heat insulator, then (T2T1)52=Pa2+4Sr2Pa1+4Sr1\left(\frac{T_2}{T_1}\right)^{\frac{5}{2}}=\frac{P_{a 2}+\frac{4 S}{r_2}}{P_{a 1}+\frac{4 S}{r_1}}.

Answer

If the surface of the bubble is a perfect heat conductor and the change in atmospheric temperature is negligible, then (r1r2)3=Pa2+4Sr2Pa1+4Sr1\left(\frac{r_1}{r_2}\right)^3=\frac{P_{a 2}+\frac{4 S}{r_2}}{P_{a 1}+\frac{4 S}{r_1}}.

Explanation

Solution

The correct answers are:
(C) If the surface of the bubble is a perfect heat conductor and the change in atmospheric temperature is negligible, then (r1r2)3=Pa2+4Sr2Pa1+4Sr1\left(\frac{r_1}{r_2}\right)^3=\frac{P_{a 2}+\frac{4 S}{r_2}}{P_{a 1}+\frac{4 S}{r_1}}.
(D) If the surface of the bubble is a perfect heat insulator, then (T2T1)52=Pa2+4Sr2Pa1+4Sr1\left(\frac{T_2}{T_1}\right)^{\frac{5}{2}}=\frac{P_{a 2}+\frac{4 S}{r_2}}{P_{a 1}+\frac{4 S}{r_1}}.