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Question: A boy walks to his school at a distance of 6 km with constant speed of 2.5 km/hour and walks back wi...

A boy walks to his school at a distance of 6 km with constant speed of 2.5 km/hour and walks back with a constant speed of 4 km/hr. His average speed for round trip expressed in km/hour, is

A

24/13

B

40/13

C

3

D

½

Answer

40/13

Explanation

Solution

Distance average speed

=2v1v2v1+v2=2×2.5×42.5+4=20065=4013km/hr= \frac{2v_{1}v_{2}}{v_{1} + v_{2}} = \frac{2 \times 2.5 \times 4}{2.5 + 4} = \frac{200}{65} = \frac{40}{13}km/hr