Question
Physics Question on laws of motion
A boy stands on a weighing machine inside a lift. When the lift is going down with acceleration g/4, the machine shows a reading 30kgf. When the lift goes upwards with acceleration g/4, the reading would be
A
18 kgf
B
37.5 kgf
C
50 kgf
D
67.5 kgf
Answer
50 kgf
Explanation
Solution
While going down, machine reading is 30 kgf. ⇒mg−N=m(4g); mg−30g=4mg;34mg=30g m=330×4=40kg While going up, the reaction would be N′−mg=m4g N′=54mg=45(40kg)g ⇒N′=50kgf.