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Question

Physics Question on laws of motion

A boy stands on a weighing machine inside a lift. When the lift is going down with acceleration g/4g/4, the machine shows a reading 30kgf30 \,kgf. When the lift goes upwards with acceleration g/4g/4, the reading would be

A

18 kgf

B

37.5 kgf

C

50 kgf

D

67.5 kgf

Answer

50 kgf

Explanation

Solution

While going down, machine reading is 30 kgf. mgN=m(g4);\Rightarrow\quad mg-N=m\left(\frac{g}{4}\right); mg30g=mg4;3mg4=30gmg-30g=\frac{mg}{4}\,;3 \frac{mg}{4}=30g m=30×43=40kgm=\frac{30\times4}{3}=40\,kg While going up, the reaction would be Nmg=mg4N^{'}-mg=m \frac{g}{4} N=5mg4=54(40kg)gN^{'}=5 \frac{mg}{4}=\frac{5}{4}\,\left(40\,kg\right)g N=50kgf.\Rightarrow\quad N^{'}=50 \,kgf.