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Question

Physics Question on mechanical properties of solids

A boy's catapult is made of rubber cord which is 42cm42\, cm long, with 6mm6\, mm diameter of cross-section and of negligible mass. The boy keeps a stone weighing 0.02kg0.02\,kg on it and stretches the cord by 20cm20\, cm by applying a constant force. When released, the stone flies off with a velocity of 20ms120\, ms^{-1}. Neglect the change in the area of cross-section of the cord while stretched. The Young's modulus of rubber is closest to:

A

104  N/m210^4 \; N/m^{-2}

B

108  N/m210^8 \; N/m^{-2}

C

106  N/m210^6 \; N/m^{-2}

D

103  N/m210^3 \; N/m^{-2}

Answer

106  N/m210^6 \; N/m^{-2}

Explanation

Solution

Energy of catapult =12×(Δ)2×Y×A×= \frac{1}{2} \times ( \frac{\Delta \ell}{\ell})^2 \times Y \times A \times \ell

= Kinetic energy of the ball =12mv2 = \frac{1}{2} mv^2 therefore,

12×(2042)2×Y×π×32×106×42×102=12×2×102×(20)2\frac{1}{2}\times\left(\frac{20}{42}\right)^{2} \times Y \times \pi \times 3^{2} \times 10^{-6} \times 42\times 10^{-2} = \frac{1}{2} \times 2 \times 10^{-2} \times \left(20\right)^{2}

Y3×106Nm2Y \simeq3 \times10^{6} Nm^{-2}