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Question: A boy playing on the roof of a 10 m high building throws a ball with a speed of 10ms<sup>–1</sup> at...

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10ms–1 at an angle of 30° with the horizontal. How far from the throwing point will the ball be the height of 10 m from the ground ?

[g=10ms–2,sin⁡30o=12,cos⁡30o=32]\left\lbrack g = 10ms^{–2},\sin 30^{o} = \frac{1}{2},\cos 30^{o} = \frac{\sqrt{3}}{2} \right\rbrack

A

8.66 m

B

5.20 m

C

4.33 m

D

2.60 m

Answer

8.66 m

Explanation

Solution

R = u2sin⁡2θg\frac{u^{2}\sin 2\theta}{g}