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Question

Physics Question on Motion in a straight line

A boy of 50kg50\, kg is standing in a left moving down with acceleration 9.8m/s2 9.8\,m/s^{2} . The apparent weight of the boy is:

A

509.8N\frac{50}{9.8}N

B

50×9.8N50\times 9.8\,N

C

50N50\, N

D

zero

Answer

zero

Explanation

Solution

Mass of the boy m=50m=50 Acceleration of lift (downwards) a=9.8m/s2a=9.8\, m / s ^{2} The apparent weight of the boy when the lift is moving downwards w=m(ga)=50(9.89.8)=0w=m(g-a)=50(9.8-9.8)=0