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Question

Physics Question on Pressure

A boy has 60kg60\, kg weight. He wants to swim in a river with the help of a wooden log. If relative density of wood is 0.60.6. What is the minimum volume of wooden log? (Density of river water is 1000kg/m31000\, kg / m ^{3} )

A

0.66m3 0.66\,m^{3}

B

150m3 150\,m^{3}

C

31m3 \frac{3}{1}\,m^{3}

D

320m3 \frac{3}{20}\,m^{3}

Answer

320m3 \frac{3}{20}\,m^{3}

Explanation

Solution

From Archimedes principle Weight of (boy + log) = weight of water displaced (60+V×0.6×103)g=V×103g(60+V \times 0.6 \times 10^{3})g=V \times 10^{3} g
0.4×103V=60\Rightarrow 0.4 \times 10^{3}V=60
V=600.4×103=600400=320m3\Rightarrow V=\frac{60}{0.4 \times 10^{3}}=\frac{600}{400}=\frac{3}{20}m^{3}