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Question

Physics Question on projectile motion

A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone will be?

A

20 m20 \ m

B

202 m20\sqrt 2 \ m

C

10 m10\ m

D

102 m10\sqrt 2 \ m

Answer

20 m20 \ m

Explanation

Solution

For vertically projected up body maximum height (H)(H),
H=u2(2g)H=\frac {u^2}{(2g)} .......(ii).......(ii)
For the same body with same initial velocity the horizontal distance traveled when thrown at an angle (θ)(θ),
R=u2gR=\frac {u^2}{g} ......(ii)......(ii)
Compare eq (i)(i) and eq (ii)(ii)
R=2HR=2H
R=2×10R=2×10
R=20 mR=20\ m

So, the correct oiption is (A): 20 m20\ m.