Question

A boy and a man carry a uniform rod of length L horizontally in such a way that boy gets (1/4)th load. If the boy is at one end of the rod, the distance of the man from the other end is -

• A. $\frac{L}{3}$
• B. $\frac{L}{4}$
• C. $\frac{2L}{3}$
• D. $\frac{3L}{4}$

Answer 1

Answer: (A)

$\frac{L}{3}$

Answer 2

Q N₁ = $\frac{W}{4}$ \ N₂ = W – $\frac{W}{4} = \frac{3W}{4}$

Also N₁ × $\frac{L}{2}$ = N₂ × $\left( \frac{L}{2} - x \right)$Ž $\frac{W}{4} \times \frac{L}{2} = \frac{3W}{4} \times \left( \frac{L}{2} - x \right)$ Ž x = $\frac{L}{3}$