Question

A box of T L-capacity ls'divided into two equal compartments by a thin partition which are filled with 2 g $H_2$ and 16 g $CH_4$ respectively. The pressure in compartment filled with $H_2$ is recorded as P atm. The total pressure when partition is removed will be

• A. p
• B. 2p
• C. P/2
• D. p/4

Answer 1

Answer: (A)

p

Answer 2

500 mL 500 mL 2 g $H_2$ 16 g $CH_4$ $PH_2$ $P_{CH4}$ $P = \frac{nRT}{V} = \frac{m\,RT}{MV}$ ($m$ = mass of gas, M = Molecular mass) $P_{H_2} = \frac{2 \, RT}{2 \times 500} = \frac{RT}{500}$ = P (given) $P_{CH_4} = \frac{16 \, RT}{16 \times 500} = \frac{RT}{500} = P_{H_2} = P$ Partial pressure of $H_2$ $P_{H_2} = \frac{2 \times RT}{2 \times 1000} = \frac{RT}{1000} = \frac{P}{2}$ Partial pressure of $CH_4$ $P_{CH_4} =\frac{16 \times RT}{16 \times 1000} = \frac{RT}{1000} = \frac{P}{2}$ $P_{Total} = P_{H_2} + P_{CH_4}$= P/2 + P/2 = I