Question

A box contains 10 mangoes out of which 4 are rotten. 2 mangoes are taken out together. If one of them is found to be good, the probability that the other is also good is

• A. 1/3
• B. 8/15
• C. 5/18
• D. 2/3

Answer 1

Answer: (C)

5/18

Answer 2

Number of ways of selecting two good mangoes

= $6C_{2} = 15$ Number of ways that at least one of the two selected mangoes is to be good = $6C_{1}x^{9}C_{1} = 54$.

∴ Required probability = $\frac{15}{64} = \frac{5}{18}$