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Question

Physics Question on radiation

A bowl filled with very hot soup cools from 98C98^{\circ} C to 86C86^{\circ} C in 2 minutes when the room temperature is 22C22^{\circ} C. How long it will take to cool from 75C75^{\circ} C to 69C69^{\circ} C ?

A

2 minutes

B

1 minute

C

1.41.4 minutes

D

0.50.5 minute

Answer

1.41.4 minutes

Explanation

Solution

ΔQΔt=K(TT0)\frac{Δ_Q}{Δ_t}​=−K(T−T_0​)

ΔQΔt=K(TavgT0)\frac{Δ_Q}{Δ_t}​=−K(T_{avg}​−T_0​)

(i) ms×122=K  (98+86222)\frac{ms×12}{2}​=−K\;\bigg(\frac{98+86}{2}​−22\bigg)

6=Kms[98+86222]6=-\frac{K}{ms}\bigg[\frac{98+86}{2}​−22\bigg]

6=Kms[70]6=−\frac{K}{ms}[70]….….. (i)


(ii) ms×6t=K(75+69222)\frac{ms×6}{\triangle_t}​=−K\bigg(\frac{75+69​}{2}−22\bigg)

6Δt=Kms(50)\frac{6}{Δ_t}​=−\frac{K}{ms}​(50).....(ii)

(ii) ÷ (i)

6Δt(6)=7050\frac{6}{Δ_t(6)}​=\frac{70}{50}​

Δt=75Δ_t=\frac{7}{5}​

=1.4  min1.4\;min