Question
Physics Question on radiation
A bowl filled with very hot soup cools from 98∘C to 86∘C in 2 minutes when the room temperature is 22∘C. How long it will take to cool from 75∘C to 69∘C ?
A
2 minutes
B
1 minute
C
1.4 minutes
D
0.5 minute
Answer
1.4 minutes
Explanation
Solution
ΔtΔQ=−K(T−T0)
ΔtΔQ=−K(Tavg−T0)
(i) 2ms×12=−K(298+86−22)
6=−msK[298+86−22]
6=−msK[70]….….. (i)
(ii) △tms×6=−K(275+69−22)
Δt6=−msK(50).....(ii)
(ii) ÷ (i)
Δt(6)6=5070
Δt=57
=1.4min