Question

A bomb is dropped on an enemy post by an aeroplane flying with a horizontal velocity of 60 km/hr and at a height of 490 m. How far the aeroplane must be from the enemy post at time of dropping the bomb, so that it may directly hit the target. (g = 9.8 m/s²)

• A. $\frac{100}{3}m$
• B. $\frac{500}{3}m$
• C. $\frac{200}{3}m$
• D. Zero

Answer 1

Answer: (B)

$\frac{500}{3}m$

Answer 2

$S = u \times t = u \times \sqrt{\frac{2h}{g}}$ $= 60 \times \frac{5}{18} \times \sqrt{\frac{2 \times 490}{9.8}} = \frac{500}{3}m$