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Question: A bolt of mass 0.2 kg falls from the ceiling of an elevator moving down with an uniform speed of \(5...

A bolt of mass 0.2 kg falls from the ceiling of an elevator moving down with an uniform speed of 5 ms15 \mathrm {~ms} ^ { - 1 }. It hits the floor of the elevator (length of the elevator = 5 m) and does not rebound. The amount of heat produced by the impact is (Take g=10 ms2\mathrm { g } = 10 \mathrm {~ms} ^ { - 2 })

A

5 J

B

10 J

C

15 J

D

20 J

Answer

10 J

Explanation

Solution

Here, m = 0.2 kg. v= 5 ms-1

h = length of elevator = 5m

As relative velocity of the bolt w.r.t. elevator is zero therefore, in the impact, only potential energy of the bolt is converted into heat energy.

Amount of heat produced

= potential energy lost by the ball

= mgh

= (0.2 kg) (10 m s-2) (5m) = 10J