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Question: A body weights W in air and it loses its weight by 25% in water. The relative density of the body is...

A body weights W in air and it loses its weight by 25% in water. The relative density of the body is:

A

4

B

1/4

C

3/4

D

4/3

Answer

1/4

Explanation

Solution

Relative density = Specific gravity R.D

=

= WaWaWw=WaΔW\frac { \mathrm { W } _ { \mathrm { a } } } { \mathrm { Wa } - \mathrm { W } _ { \mathrm { w } } } = \frac { \mathrm { W } _ { \mathrm { a } } } { \Delta \mathrm { W } } =

[since weight of the body decreases by 25 % of its original

weight Wa (weight in air)].

⇒ R.D. = 4.

Therefore (2).