Question

A body weighs 1 kg by a spring balance at the north pole. What will it weigh at the equator ?

• A. 0.977 kg
• B. 0.967 kg
• C. 0.987 kg
• D. 0.997 kg

Answer 1

Answer: (D)

0.997 kg

Answer 2

mg'= mg$\left\lbrack 1 - \frac{R\omega^{2}}{g} \right\rbrack$

= 1$\left\lbrack 1 - \frac{6400 \times 10^{3} \times (2\pi)^{2}}{10 \times (3600 \times 24)^{2}} \right\rbrack = 0.997kg$