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Question

Physics Question on Motion in a straight line

A body travelling along a straight line traverse one-third the distance with a velocity of 5m/s5 \,m/s . The remaining part of the distance was covered with velocity 3m/s3 \,m/s for half the time and with velocity 2m/s2 \,m/s for the other half of the time. The average velocity of the body over the whole time of motion will be

A

3m/s3\, m/s

B

5m/s5\, m/s

C

2m/s2\, m/s

D

2.5m/s2.5\, m/s

Answer

5m/s5\, m/s

Explanation

Solution

Time taken in the one third part of total distance coverd is t1t_1 and for remaining part is 2t22t_2
t1=x/35=x15t_1 = \frac{x/3}{5} = \frac{x}{15}
x1+x2=23xx_1 + x_2 = \frac{2}{3} x
3t2+2t2=23x3t_2 + 2t_2 = \frac{2}{3} x
5t2=23x5t_2 = \frac{2}{3}x
t2=2x15t_2 = \frac{2x}{15}
Total time =t1+2t2 = t_1 + 2t_2
=x15+2x15= \frac{x}{15} + \frac{2x}{15}
t=3x15=x5t = \frac{3x}{15} = \frac{x}{5}
Average velocity
v=xx5v = \frac{x}{\frac{x}{5}}
v=5m/sv = 5\,m/s