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Question: A body thrown with an initial speed of \(96ft/\sec\) reaches the ground after \((g = 32ft/\sec^{2})\...

A body thrown with an initial speed of 96ft/sec⁡96ft/\sec reaches the ground after (g=32ft/sec⁡2)(g = 32ft/\sec^{2})

A

3 sec

B

6 sec

C

12 sec

D

8 sec

Answer

6 sec

Explanation

Solution

Time of flight =2ug=2×9632=6 6musec⁡= \frac{2u}{g} = \frac{2 \times 96}{32} = 6\mspace{6mu}\sec