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Question: A body takes T minutes to cool from 62<sup>0</sup>C to 61<sup>0</sup>C when the surrounding temperat...

A body takes T minutes to cool from 620C to 610C when the surrounding temperature is 300C. The time taken by the body to cool from 460C to 45.50C is

A

Greater than T minutes

B

Equal to T minutes

C

Less than T minutes

D

Equal to T/2 minutes

Answer

Equal to T minutes

Explanation

Solution

According to Newton's law of cooling

θ1θ2t[θ1+θ22θ]\frac{\theta_{1} - \theta_{2}}{t} \propto \left\lbrack \frac{\theta_{1} + \theta_{2}}{2} - \theta \right\rbrack

For first condition 6261T[62+61230]\frac{62 - 61}{T} \propto \left\lbrack \frac{62 + 61}{2} - 30 \right\rbrack …..(i)

and for second condition 4645.5t[46+45.5230]\frac{46 - 45.5}{t} \propto \left\lbrack \frac{46 + 45.5}{2} - 30 \right\rbrack .(ii)

By solving (i) and (ii) we get t = T sec.