Question

A body starts to fall freely under gravity. The distance covered by it in first, second and third second are in ratio

• A. 1:03:05
• B. 1:02:03
• C. 1:04:09
• D. 1:05:06

Answer 1

Answer: (A)

1:03:05

Answer 2

Distance covered in $n^{\text {th }}$ sec. $s_{n}=u+\frac{a}{2}(2 n-1)$ $\because$ $u=0$ So, $s_{n}=\frac{a}{2}(2 n-1)$, $a$ is constant Therefore, $s_{1}: s_{2}: s_{3}$ $=\\{2(1)-1\\}:\\{2(2)-1\\}:\\{2(3)-1\\}$ $=1: 3: 5$