Question

A body starts to fall freely under gravity. The distances covered by it in first, second and third seconds are in ratio

• A. $1:3:5$
• B. $1:2:3$
• C. $1:4:9$
• D. $1:5:6$

Answer 1

Answer: (A)

$1:3:5$

Answer 2

According to equation of motion distance covered in nth second. $S_{n}=u+\frac{a}{2}(2 n-1)$ $S_{n}=\frac{a}{2}(2 n-1)$ $(\because u=0)$ $\therefore S_{1}: S_{2} : S_{3}$ $=\\{2(1)-1\\}:\\{2(2)-1\\}:\\{2(3)-1\\}$ $=1: 3: 5$