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Question: A body starts from the origin with an acceleration of 6 m/s<sup>2</sup> along the x-axis and 8 m/s<s...

A body starts from the origin with an acceleration of 6 m/s2 along the x-axis and 8 m/s2 along the y-axis. Its distance from the origin after 4 seconds will be

A

56 m

B

64 m

C

80 m

D

128 m

Answer

80 m

Explanation

Solution

Displacement along X- axis : x=uxt+12axt2x = u_{x}t + \frac{1}{2}a_{x}t^{2}

=12×6×(4)2=48m= \frac{1}{2} \times 6 \times (4)^{2} = 48m

Displacement along Y- axis :

y=uyt+12ayt2=12×8×(4)2=64my = u_{y}t + \frac{1}{2}a_{y}t^{2} = \frac{1}{2} \times 8 \times (4)^{2} = 64m

Total distance from the origin

=x2+y2=(48)2+(64)2=80m= \sqrt{x^{2} + y^{2}} = \sqrt{(48)^{2} + (64)^{2}} = 80m