Question

a body standing on a long railroad car throws a ball straight upwards, the car is moving on the horizontal road with an acceleration 1 ms^-2. The vertical velocity given is 9.8 ms^-1. How far behind the body the ball will fall on the railroad car?

• A. 1 m
• B. 3/2 m
• C. 7/4 m
• D. 2 m

Answer 1

Answer: (D)

2 m

Answer 2

T = $\frac{2u_{y}}{g}$ = 2 × $\frac{9.8}{9.8}$ = 2s;

x = $\frac{1}{2}a_{x}t^{2} = \frac{1}{2}(1)(2)^{2} = 2m$.