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Question

Question: A body slides down a frictionless track which ends in a circular loop of diameter D, then the minimu...

A body slides down a frictionless track which ends in a circular loop of diameter D, then the minimum height h of the body in term of D so that it may just complete the loop, is

A

h=5D2h = \frac{5D}{2}

B

h=5D4h = \frac{5D}{4}

C

h=3D4h = \frac{3D}{4}

D

h=D4h = \frac{D}{4}

Answer

h=5D4h = \frac{5D}{4}

Explanation

Solution

We know h=52rh = \frac{5}{2}r =52(D2)=5D4= \frac{5}{2}\left( \frac{D}{2} \right) = \frac{5D}{4} [For critical condition of vertical looping]