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Question: A body of weight 64 N is pushed with just enough force to start it moving across a horizontal floor ...

A body of weight 64 N is pushed with just enough force to start it moving across a horizontal floor and the same force continues to act afterwards. If the coefficients of static and dynamic friction are 0.6 and 0.4 respectively, the acceleration of the body will be (Acceleration due to gravity = g)

A

g6.4\frac{g}{6.4}

B

0.64 g

C

g32\frac{g}{32}

D

0.2 g

Answer

0.2 g

Explanation

Solution

Limiting friction = Fl=μsRF_{l} = \mu_{s}R ⇒ 64 = 0.6 m g

⇒ m =640.6g\frac{64}{0.6g}.

Acceleration = Applied force – Kinetic frictionMass of the body\frac{\text{Applied force }\text{–}\text{ Kinetic friction}}{\text{Mass of the body}}=

64μKmgm\frac{64 - \mu_{K}mg}{m}=640.4×640.6640.6g\frac{64 - 0.4 \times \frac{64}{0.6}}{\frac{64}{0.6g}}= 0.2g