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Question: A body of mass x kg is moving with the velocity of \(100\text{ }m\text{ }{{\sec }^{-1}}\) . Its de B...

A body of mass x kg is moving with the velocity of 100 m sec1100\text{ }m\text{ }{{\sec }^{-1}} . Its de Broglie wavelength is6.62×1035m6.62\times {{10}^{-35}}m. Hence x is:
[h=6.62×1034Jsec]\left[ h=6.62\times {{10}^{-34}}J-\sec \right]
A. 0.25 kg
B. 0.15 kg
C. 0.2 kg
D. 0.1 kg

Explanation

Solution

It is found that de Broglie wavelength is associated with an object, in relation to its mass and momentum. de Broglie equation for wavelength is given by the formula: λ=hmv\lambda =\frac{h}{mv}
Where, λ\lambda is the wavelength, h is the plank constant, m is the mass of the body and v is the velocity .

Complete step by step answer:
- We are being provided with the value of wavelength λ\lambda =6.62×1035m6.62\times {{10}^{-35}}m
velocity is100 m sec1100\text{ }m\text{ }{{\sec }^{-1}} and [h=6.62×1034Jsec]\left[ h=6.62\times {{10}^{-34}}J-\sec \right]
- We will find the mass of the body as x.
- As we know that de Broglie equation for wavelength is given by the formula λ=hmv\lambda =\frac{h}{mv}
So, by putting all the values given, in the formula we get:
6.62×1035=6.62×1034Jsx×100 x=6.62×10346.62×1035 x=0.1kg \begin{aligned} & 6.62\times {{10}^{-35}}=\frac{6.62\times {{10}^{-34}}Js}{x\times 100} \\\ & x=\frac{6.62\times {{10}^{-34}}}{6.62\times {{10}^{-35}}} \\\ & x=0.1kg \\\ \end{aligned}
Hence, we can conclude that the correct option is (D), that is the mass of the body is 0.1 kg.

Additional Information:
- It was de Broglie who found that the matter can also show the wave particle duality, just like the light. As light can behave like both of the particles and as a wave.
- And he also reasoned that matter would also follow the same equation for wavelength as light.

Note:
- We should not forget to write units after solving any question.
- We can say that de Broglie concept is most important, which is used to construct microscopes that are used in the measurement of objects of very small size.