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Question: A body of mass of \(100g\) is attached to a \(1m\) long string and it is revolving in a vertical cir...

A body of mass of 100g100g is attached to a 1m1m long string and it is revolving in a vertical circle. When the string makes an angle of 60o60^{o} with the vertical then its speed is 26mum/s2\mspace{6mu} m/s. The tension in the string at θ=60o\theta = 60^{o} will be

A

896muN89\mspace{6mu} N

B

0.896muN0.89\mspace{6mu} N

C

8.96muN8.9\mspace{6mu} N

D

0.0896muN0.089\mspace{6mu} N

Answer

0.896muN0.89\mspace{6mu} N

Explanation

Solution

T=mgcosθ+mv2r=0.1×9.8×cos60+0.1×(2)21=0.49+0.4=0.89NewtonT = mg\cos\theta + \frac{mv^{2}}{r} = 0.1 \times 9.8 \times \cos 60 + \frac{0.1 \times (2)^{2}}{1} = 0.49 + 0.4 = 0.89Newton