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Question: A body of mass \(m_{1}\)is moving with a velocity V. It collides with another stationary body of mas...

A body of mass m1m_{1}is moving with a velocity V. It collides with another stationary body of mass m2.m_{2}. They get embedded. At the point of collision, the velocity of the system

A

Increases

B

Decreases but does not become zero

C

Remains same

D

Become zero

Answer

Decreases but does not become zero

Explanation

Solution

By momentum conservation before and after collision.

m1V+m2×0=(m1+m2)vm _ { 1 } V + m _ { 2 } \times 0 = \left( m _ { 1 } + m _ { 2 } \right) vv=m1m1+m2Vv = \frac { m _ { 1 } } { m _ { 1 } + m _ { 2 } } V

i.e. Velocity of system is less than V.