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Question

Question: A body of mass m moving with velocity v makes a head-on collision with another body of mass 2m which...

A body of mass m moving with velocity v makes a head-on collision with another body of mass 2m which is initially at rest. The loss of kinetic energy of the colliding body (mass m) is

A

12\frac{1}{2}of its initial kinetic energy

B

19\frac{1}{9}of its initial kinetic energy

C

89\frac{8}{9}of its initial kinetic energy

D

14\frac{1}{4}of its initial kinetic energy

Answer

89\frac{8}{9}of its initial kinetic energy

Explanation

Solution

Loss of kinetic energy of the colliding body

ΔKK=1(m1m2m1+m2)2=1(m2mm+2m)2=1(13)2ΔK=(119)K=89K\frac{\Delta K}{K} = 1 - \left( \frac{m_{1} - m_{2}}{m_{1} + m_{2}} \right)^{2} = 1 - \left( \frac{m - 2m}{m + 2m} \right)^{2} = 1 - \left( \frac{1}{3} \right)^{2}\Delta K = \left( 1 - \frac{1}{9} \right)K = \frac{8}{9}K

∴ Loss of kinetic energy is 89\frac{8}{9} of its initial kinetic energy.