Question

A body of mass $M$ moving with velocity $V$ explodes into two equal parts. If one comes to rest and the other body moves with velocity $v$, what would be the value of $v$ ?

• A. V
• B. V/$\sqrt{2}$
• C. 4V
• D. 2V

Answer 1

Answer: (D)

2V

Answer 2

Before explosion, the total momentum of the system = MV After explosion, the total momentum of the system $= \frac{M}{2}\times0+\frac{M}{2}\times v = \frac{Mv}{2}$ From the principal of momentum conservation, $MV = \frac{Mv}{2}$ $\Rightarrow v = 2V$