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Question

Physics Question on Motion in a straight line

A body of mass m'm' moving along a straight line covers half the distance with a speed of 2ms12\, ms^{-1}. The remaining half of the distance is covered in two equal time intervals with a speed of 3ms13\, ms^{-1} and 5ms15\, ms^{-1} respectively. The average speed of the particle for the entire journey is

A

83ms1\frac{8}{3}\,ms^{-1}

B

43ms1\frac{4}{3}\,ms^{-1}

C

163ms1\frac{16}{3}\,ms^{-1}

D

38ms1\frac{3}{8}\,ms^{-1}

Answer

83ms1\frac{8}{3}\,ms^{-1}

Explanation

Solution

Let the total distance travelled by the body is 2S2 S. If t1t_{1} is the time taken by the body to travel first half of the distance, then
t1=s2t_{1}=\frac{s}{2}
Let t2t_{2} be the time taken by the body for each time interval for the remaining half journey.
S=3t2+5t2=8t2\therefore \,\,\,\,S=3 t_{2}+5 t_{2}=8 t_{2}
So, average speed = Total distance travelled  Total time taken =\frac{\text { Total distance travelled }}{\text { Total time taken }}
=2St1+2t2=\frac{2 S}{t_{1}+2 t_{2}}
=2SS2+S4=\frac{2 S}{\frac{S}{2}+\frac{S}{4}}
=83ms1=\frac{8}{3} \,ms ^{-1}

So, the correct answer is (A): 83ms1\frac{8}{3}\,ms^{-1}