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Question: A body of mass m is kept on a rough horizontal surface of friction coefficientμ. A force is applied ...

A body of mass m is kept on a rough horizontal surface of friction coefficientμ. A force is applied horizontally, but the body is not moving. The net force 'F' by the surface on the body will be

A

F ≤μ mg

B

F = μ mg

C

mg≤ F ≤ mg 1+μ2\sqrt{1 + \mu^{2}}

D

mg ≥ F ≥ mg (1μ2)\sqrt{(1 - \mu^{2})}

Answer

mg≤ F ≤ mg 1+μ2\sqrt{1 + \mu^{2}}

Explanation

Solution

If the body is not moving, F = f, f is the force of friction on the body

and 0 ≤ f ≤ μmg or 0 ≤ F ≤ μmg . . . (i)

The force by the surface on the body

F = f2+R2=F2+(mg)2\sqrt{f^{2} + R^{2}} = \sqrt{F^{2} + (mg)^{2}}

or F = mg μ2+1\sqrt{\mu^{2} + 1} ∴ mg ≤ F ≤ mg 1+μ2\sqrt{1 + \mu^{2}} ,

Hence the correct choice is